If 3 men or 5 women can do a piece of work in 12 days, in how many days will 6 men and 5 women complete the same work?
A. 6 days
B. 3 days
C. 4 days
D. 5 days
Answer: Option C
Solution (By JKSSB Mock Tests)
3 Men = 5 Women => 6 Men = 10 Women. 6 men + 5 women = 10 women + 5 women = 15 women. Since 5 women take 12 days, 15 women will take (5 * 12) / 15 = 60 / 15 = 4 days.
A and B can do a piece of work in 45 and 40 days respectively. They began the work together, but A left after some days and B finished the remaining work in 23 days. After how many days did A leave?
Explanation:
Total work = LCM(45, 40) = 360 units. Efficiency of A = 8, B = 9. B worked alone for 23 days: work done = 23 * 9 = 207 units. Remaining work = 360 - 207 = 153 units. This was done by A and B together. Combined efficiency = 8 + 9 = 17. Number of days they worked together = 153 / 17 = 9 days. Thus, A left after 9 days.
A and B can complete a piece of work in 18 days and 24 days respectively. They worked together for 6 days and then A left. In how many days will B complete the remaining work?
Explanation:
Total work = LCM(18, 24) = 72 units. Efficiency of A = 4, B = 3. Combined efficiency = 7. In 6 days, work done = 6 * 7 = 42 units. Remaining work = 72 - 42 = 30 units. Time taken by B to finish remaining work = 30 / 3 = 10 days.
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