Percentage MCQs

Maths

Percentage MCQs

Practice Percentage MCQs with answers and detailed explanations. Learn percentage calculations, increase and decrease percentages, profit and loss percentages, discounts, percentage change and exam-oriented quantitative aptitude questions designed for SSC, Railway, Banking, UPSC, JKSSB, Police, Teaching and other competitive exams.

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Question #61
A student needs 30% to pass. He scores 40 marks and fails by 20 marks. What is the total marks?
A. 300
B. 250
C. 200
D. 150
Discuss
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Correct Answer: Option C

Explanation:
Passing marks = 40 + 20 = 60. 30% of Maximum = 60. Maximum = 60 * (100 / 30) = 200.
This question belongs to: Maths Percentage
Question #62
Student A gets 30% marks and fails by 15 marks. Student B gets 40% marks and gets 15 marks more than passing. What is the total marks?
A. 400
B. 300
C. 250
D. 350
Discuss
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Correct Answer: Option B

Explanation:
Difference in percentage = 40% - 30% = 10%. Difference in marks = 15 - (-15) = 30. 10% of Maximum = 30. Maximum = 300.
This question belongs to: Maths Percentage
Question #63
Student A gets 20% marks and fails by 30 marks. Student B gets 32% marks and gets 42 marks more than passing. Find the total marks.
A. 800
B. 700
C. 600
D. 500
Discuss
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Correct Answer: Option C

Explanation:
Difference in percentage = 32% - 20% = 12%. Difference in marks = 42 + 30 = 72. 12% of Total = 72. Total = 600.
This question belongs to: Maths Percentage
Question #64
Student A gets 25% marks and fails by 20 marks. Student B gets 40% marks and passes by 40 marks. Find the total marks.
A. 600
B. 400
C. 300
D. 500
Discuss
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Correct Answer: Option B

Explanation:
Difference in percentage = 40% - 25% = 15%. Difference in marks = 40 + 20 = 60. 15% of Total = 60. Total = 400.
This question belongs to: Maths Percentage
Question #65
A student gets 180 marks and fails by 30 marks. The passing percentage is 35%. What is the total marks?
A. 700
B. 500
C. 600
D. 800
Discuss
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Correct Answer: Option C

Explanation:
Passing marks = 180 + 30 = 210. 35% of Total = 210. Total = 210 * (100 / 35) = 600.
This question belongs to: Maths Percentage
Question #66
A student gets 200 marks and fails by 25 marks. If the passing marks are 45%, find the maximum marks.
A. 450
B. 500
C. 550
D. 600
Discuss
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Correct Answer: Option B

Explanation:
Passing marks = 200 + 25 = 225. 45% of Maximum = 225. Maximum = 225 * (100 / 45) = 500.
This question belongs to: Maths Percentage
Question #67
A student scored 60% marks, which is 60 marks more than the pass marks. If the pass marks is 40%, find the maximum marks.
A. 350
B. 300
C. 400
D. 250
Discuss
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Correct Answer: Option B

Explanation:
Difference in percentage = 60% - 40% = 20%. 20% of Maximum = 60 marks. Maximum = 60 * 5 = 300.
This question belongs to: Maths Percentage
Question #68
A student gets 75% marks, which is 90 marks more than the passing marks. If the passing requirement is 45%, what is the maximum marks?
A. 350
B. 300
C. 400
D. 250
Discuss
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Correct Answer: Option B

Explanation:
Difference = 75% - 45% = 30%. 30% of Maximum = 90. Maximum = 90 * (100 / 30) = 300.
This question belongs to: Maths Percentage
Question #69
The population of a town is 10,000. It increases by 10% annually. What will be the population after 2 years?
A. 12000
B. 12200
C. 12100
D. 11000
Discuss
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Correct Answer: Option C

Explanation:
Population = P * (1 + R/100)^t = 10000 * (1.10)^2 = 10000 * 1.21 = 12100.
This question belongs to: Maths Percentage
Question #70
The population of a town is 20,000. It increases by 5% annually. What will be the population after 2 years?
A. 21000
B. 22050
C. 22100
D. 22000
Discuss
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Correct Answer: Option B

Explanation:
Population = 20000 * (1.05)^2 = 20000 * 1.1025 = 22050.
This question belongs to: Maths Percentage
Question #71
The population of a village is 5,000. It increases by 20% annually. What will be the population after 2 years?
A. 7200
B. 7000
C. 7400
D. 6000
Discuss
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Correct Answer: Option A

Explanation:
Population = 5000 * (1.20)^2 = 5000 * 1.44 = 7200.
This question belongs to: Maths Percentage
Question #72
The value of a machine is 10,000. It depreciates by 10% annually. What will be its value after 2 years?
A. 8200
B. 9000
C. 8100
D. 8000
Discuss
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Correct Answer: Option C

Explanation:
Value = P * (1 - R/100)^t = 10000 * (0.90)^2 = 10000 * 0.81 = 8100.
This question belongs to: Maths Percentage
Question #73
The value of a machine is 8,000. It depreciates by 20% annually. What will be its value after 2 years?
A. 5120
B. 6000
C. 6400
D. 5200
Discuss
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Correct Answer: Option A

Explanation:
Value = 8000 * (0.80)^2 = 8000 * 0.64 = 5120.
This question belongs to: Maths Percentage
Question #74
A town's population was 100,000 and is now 121,000. If the annual increase is 10%, in how many years did this increase occur?
A. 2
B. 3
C. 1
D. 4
Discuss
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Correct Answer: Option A

Explanation:
121000 = 100000 * (1.10)^t. 1.21 = (1.10)^t. Since 1.10^2 = 1.21, t = 2 years.
This question belongs to: Maths Percentage
Question #75
The present population of a town is 10,890. If it increases by 10% yearly, what was its population 2 years ago?
A. 9500
B. 10000
C. 8000
D. 9000
Discuss
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Correct Answer: Option D

Explanation:
P_past = P_present / (1 + R/100)^2 = 10890 / (1.10)^2 = 10890 / 1.21 = 9000.
This question belongs to: Maths Percentage
Question #76
The present value of a machine is 7,290. If it depreciates by 10% yearly, what was its value 3 years ago?
A. 12000
B. 9000
C. 11000
D. 10000
Discuss
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Correct Answer: Option D

Explanation:
V_past = 7290 / (0.90)^3 = 7290 / 0.729 = 10000.
This question belongs to: Maths Percentage
Question #77
A population increases by 5% yearly. Its present population is 88,200. What was it 2 years ago?
A. 84000
B. 82000
C. 78000
D. 80000
Discuss
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Correct Answer: Option D

Explanation:
P_past = 88200 / (1.05)^2 = 88200 / 1.1025 = 80000.
This question belongs to: Maths Percentage
Question #78
A population increases by 20% in the first year and decreases by 20% in the second year. What is the net change over the two years?
A. 2% decrease
B. No change
C. 4% increase
D. 4% decrease
Discuss
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Correct Answer: Option D

Explanation:
Net change = (20)^2 / 100 = 4% decrease.
This question belongs to: Maths Percentage
Question #79
A student multiplied a number by 3/5 instead of 5/3. What is the percentage error in the calculation?
A. 36%
B. 60%
C. 40%
D. 64%
Discuss
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Correct Answer: Option D

Explanation:
True value = 5/3x. False value = 3/5x. Error = (5/3 - 3/5)x = (16/15)x. % Error = ((16/15) / (5/3)) * 100 = (16/25) * 100 = 64%.
This question belongs to: Maths Percentage
Question #80
A student multiplied a number by 4/5 instead of 5/4. What is the percentage error?
A. 30%
B. 36%
C. 45%
D. 25%
Discuss
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Correct Answer: Option B

Explanation:
Error = (5/4 - 4/5)x = (9/20)x. % Error = ((9/20) / (5/4)) * 100 = (9/25) * 100 = 36%.
This question belongs to: Maths Percentage

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