Time and Work MCQs

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Time and Work MCQs

Practice Time and Work MCQs with answers and detailed solutions. Learn work efficiency, pipes and cisterns, men and women work problems, partnership, wages, productivity and advanced aptitude questions commonly asked in competitive exams.

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Question #121
A is twice as fast as B. If A and B together can complete a piece of work in 8 days, in how many days can A alone complete it?
A. 16 days
B. 10 days
C. 24 days
D. 12 days
Discuss
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Correct Answer: Option D

Explanation:
Let efficiency of B = 1, then efficiency of A = 2. Combined efficiency = 3 units/day. Total work = 8 * 3 = 24 units. Time taken by A alone = 24 / 2 = 12 days.
This question belongs to: Maths Time and Work
Question #122
A can complete a piece of work in 12 days and B in 15 days. They work together for 3 days and then B leaves. In how many days will A complete the remaining work?
A. 5.6 days
B. 7.5 days
C. 4.8 days
D. 6.6 days
Discuss
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Correct Answer: Option D

Explanation:
Total work = LCM(12, 15) = 60 units. Efficiency of A = 5, B = 4. Combined efficiency = 9 units/day. In 3 days, work completed = 3 * 9 = 27 units. Remaining work = 60 - 27 = 33 units. Time taken by A to complete remaining work = 33 / 5 = 6.6 days.
This question belongs to: Maths Time and Work
Question #123
If 5 men can complete a work in 6 days, and 10 women can complete the same work in 5 days, in how many days can 5 men and 5 women complete the work together?
A. 4 days
B. 3 days
C. 3.75 days
D. 4.5 days
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Correct Answer: Option C

Explanation:
Efficiency of 5 men = 1/6. Efficiency of 10 women = 1/5, so efficiency of 5 women = 1/10. Combined efficiency of 5 men and 5 women = 1/6 + 1/10 = (5 + 3) / 30 = 8 / 30 = 4 / 15. Time taken together = 15 / 4 = 3.75 days.
This question belongs to: Maths Time and Work
Question #124
A, B and C can complete a piece of work in 12, 15 and 20 days respectively. A and B start working together and after 2 days A leaves and C joins B. In how many more days will the work be completed?
A. 7 days
B. 4 days
C. 6 days
D. 5 days
Discuss
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Correct Answer: Option C

Explanation:
Total work = LCM(12, 15, 20) = 60 units. Efficiency of A = 5, B = 4, C = 3. In 2 days, A and B complete 2 * (5 + 4) = 18 units. Remaining work = 60 - 18 = 42 units. Now, B and C work together with combined efficiency = 4 + 3 = 7 units/day. Time taken to complete the remaining work = 42 / 7 = 6 days.
This question belongs to: Maths Time and Work
Question #125
A can complete a piece of work in 18 days, B in 24 days and C in 36 days. If they work together, in how many days will they finish the work?
A. 6 days
B. 8 days
C. 9 days
D. 7 days
Discuss
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Correct Answer: Option B

Explanation:
Total work = LCM(18, 24, 36) = 72 units. Efficiency of A = 4, B = 3, C = 2. Combined efficiency = 4 + 3 + 2 = 9 units/day. Time taken together = 72 / 9 = 8 days.
This question belongs to: Maths Time and Work
Question #126
A is 25% more efficient than B. If they working together can finish a work in 20 days, then in how many days can B alone finish it?
A. 45 days
B. 50 days
C. 36 days
D. 40 days
Discuss
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Correct Answer: Option A

Explanation:
Let efficiency of B = 4, then efficiency of A = 5. Combined efficiency = 9 units/day. Total work = 20 * 9 = 180 units. Time taken by B alone = 180 / 4 = 45 days.
This question belongs to: Maths Time and Work
Question #127
A can do a piece of work in 12 days and B can do the same work in 18 days. They work together for 4 days and then A leaves. How many days will B take to complete the remaining work?
A. 6 days
B. 7 days
C. 5 days
D. 8 days
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Correct Answer: Option D

Explanation:
Total work = LCM(12, 18) = 36 units. Efficiency of A = 3, B = 2. Combined efficiency = 5. In 4 days, work completed = 4 * 5 = 20 units. Remaining work = 36 - 20 = 16 units. Time taken by B to complete the remaining work = 16 / 2 = 8 days.
This question belongs to: Maths Time and Work
Question #128
If 6 men and 8 boys can do a piece of work in 10 days, then 3 men and 4 boys will do the same work in:
A. 20 days
B. 15 days
C. 12 days
D. 5 days
Discuss
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Correct Answer: Option A

Explanation:
The number of workers (3 men and 4 boys) is exactly half of the original group (6 men and 8 boys). Since efficiency becomes half, the time taken will double. Total time = 10 * 2 = 20 days.
This question belongs to: Maths Time and Work
Question #129
A, B and C can do a piece of work in 10, 15 and 30 days respectively. If they work on alternate days in the order A, B, C, in how many days will the work be completed?
A. 12 days
B. 20 days
C. 15 days
D. 18 days
Discuss
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Correct Answer: Option C

Explanation:
Total work = LCM(10, 15, 30) = 30 units. Efficiency of A = 3, B = 2, C = 1. In a 3-day cycle (A on day 1, B on day 2, C on day 3), work completed = 3 + 2 + 1 = 6 units. Number of cycles required = 30 / 6 = 5 cycles. Total days = 5 * 3 = 15 days.
This question belongs to: Maths Time and Work
Question #130
A and B can complete a work in 12 days and 16 days respectively. Both work together for 3 days and then A leaves. How long will B take to complete the remaining work?
A. 10 days
B. 11 days
C. 9 days
D. 8 days
Discuss
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Correct Answer: Option C

Explanation:
Total work = LCM(12, 16) = 48 units. Efficiency of A = 4, B = 3. Combined efficiency = 7 units/day. In 3 days, work completed = 3 * 7 = 21 units. Remaining work = 48 - 21 = 27 units. Time taken by B to complete remaining work = 27 / 3 = 9 days.
This question belongs to: Maths Time and Work
Question #131
If 5 men or 9 women can do a piece of work in 19 days, then 3 men and 6 women will do the same work in:
A. 15 days
B. 12 days
C. 10 days
D. 13 days
Discuss
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Correct Answer: Option A

Explanation:
5 Men = 9 Women => 1 Man = 9/5 Women. 3 men + 6 women = 3 * (9/5) + 6 = 27/5 + 6 = 57/5 women. Since 9 women take 19 days, 57/5 women will take (9 * 19) / (57/5) = (171 * 5) / 57 = 3 * 5 = 15 days.
This question belongs to: Maths Time and Work
Question #132
A can complete a piece of work in 14 days and B in 21 days. They begin together but A leaves 3 days before the completion of the work. Find the total number of days taken to complete the work.
A. 11 days
B. 9(1/5) days
C. 8(3/5) days
D. 10(1/5) days
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Correct Answer: Option D

Explanation:
Total work = LCM(14, 21) = 42 units. Efficiency of A = 3, B = 2. Let total days be x. A works for (x - 3) days, B works for x days. 3(x - 3) + 2x = 42 => 3x - 9 + 2x = 42 => 5x = 51 => x = 51/5 = 10(1/5) days.
This question belongs to: Maths Time and Work
Question #133
A and B can do a job in 6 days and 12 days respectively. They began the work together but A left after 3 days. In how many days was the remaining work completed by B?
A. 4 days
B. 3 days
C. 2 days
D. 5 days
Discuss
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Correct Answer: Option B

Explanation:
Total work = LCM(6, 12) = 12 units. Efficiency of A = 2, B = 1. Combined efficiency = 3 units/day. In 3 days, work done = 3 * 3 = 9 units. Remaining work = 12 - 9 = 3 units. Time taken by B to complete remaining work = 3 / 1 = 3 days.
This question belongs to: Maths Time and Work
Question #134
12 men can complete a piece of work in 36 days. In how many days will 18 men complete the same work?
A. 30 days
B. 18 days
C. 24 days
D. 28 days
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Correct Answer: Option C

Explanation:
Using M1 * D1 = M2 * D2: 12 * 36 = 18 * D2 => D2 = (12 * 36) / 18 = 12 * 2 = 24 days.
This question belongs to: Maths Time and Work
Question #135
A is 50% more efficient than B. C does half of the work done by A and B together in the same time. If C alone can do the work in 30 days, then A, B and C together can do the work in:
A. 10 days
B. 15 days
C. 12 days
D. 20 days
Discuss
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Correct Answer: Option A

Explanation:
Let efficiency of B = 2, then efficiency of A = 3. Combined efficiency of A and B = 5. Efficiency of C = 5 / 2 = 2.5. Total work = Efficiency of C * Time of C = 2.5 * 30 = 75 units. Combined efficiency of A, B and C = 3 + 2 + 2.5 = 7.5 units/day. Time taken together = 75 / 7.5 = 10 days.
This question belongs to: Maths Time and Work
Question #136
A, B and C can complete a work in 12, 15 and 20 days respectively. If they work together, in how many days will the work be completed?
A. 4 days
B. 6 days
C. 4.5 days
D. 5 days
Discuss
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Correct Answer: Option D

Explanation:
Total work = LCM(12, 15, 20) = 60 units. Efficiency of A = 5, B = 4, C = 3. Combined efficiency = 5 + 4 + 3 = 12 units/day. Time taken together = 60 / 12 = 5 days.
This question belongs to: Maths Time and Work
Question #137
A can do a piece of work in 15 days and B in 20 days. They began the work together but A left after 4 days. In how many days will B complete the remaining work?
A. 10(2/3) days
B. 8 days
C. 9(1/3) days
D. 10(1/3) days
Discuss
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Correct Answer: Option A

Explanation:
Total work = LCM(15, 20) = 60 units. Efficiency of A = 4, B = 3. Combined efficiency = 7. In 4 days, work completed = 4 * 7 = 28 units. Remaining work = 60 - 28 = 32 units. Time taken by B to complete remaining work = 32 / 3 = 10(2/3) days.
This question belongs to: Maths Time and Work
Question #138
If 3 men or 5 women can do a piece of work in 12 days, in how many days will 6 men and 5 women complete the same work?
A. 3 days
B. 6 days
C. 4 days
D. 5 days
Discuss
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Correct Answer: Option C

Explanation:
3 Men = 5 Women => 6 Men = 10 Women. 6 men + 5 women = 10 women + 5 women = 15 women. Since 5 women take 12 days, 15 women will take (5 * 12) / 15 = 60 / 15 = 4 days.
This question belongs to: Maths Time and Work
Question #139
A can do a work in 18 days and B in 24 days. They start together but A leaves 3 days before the completion of the work. Find the total number of days taken to complete the work.
A. 13 days
B. 10 days
C. 11 days
D. 12 days
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Correct Answer: Option D

Explanation:
Total work = LCM(18, 24) = 72 units. Efficiency of A = 4, B = 3. Let total days be x. A works for (x - 3) days, B works for x days. 4(x - 3) + 3x = 72 => 4x - 12 + 3x = 72 => 7x = 84 => x = 12 days.
This question belongs to: Maths Time and Work
Question #140
A is 40% more efficient than B. If they together can finish a work in 10 days, in how many days can A alone finish it?
A. 15 days
B. 14 days
C. 16(2/3) days
D. 17(1/7) days
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Correct Answer: Option D

Explanation:
Let efficiency of B = 5, then efficiency of A = 7. Combined efficiency = 12 units/day. Total work = 10 * 12 = 120 units. Time taken by A alone = 120 / 7 = 17(1/7) days.
This question belongs to: Maths Time and Work

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